4X - 2X - 2 = - 42 preform the indicated variable subtraction ( 4X - 2X ) 2X - 2 = - 42 add 2 to each side 2X = - 40 divide both sides integers by 2 X = - 20 -------------check in original equation 4(- 20) - 2(- 20) - 2 = - 42 - 80 + 40 - 2 = - 42 - 42 = - 42 ---------------checks
2 because 22+42 = 20
20 percent of 42 = 8.4
86 - 42 = 44
If you mean points of (2, -3) and (4, 2) then the slope is 5/2 and the straight line equation is 2y = 5x-16
-36
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
4X - 2X - 2 = - 42 preform the indicated variable subtraction ( 4X - 2X ) 2X - 2 = - 42 add 2 to each side 2X = - 40 divide both sides integers by 2 X = - 20 -------------check in original equation 4(- 20) - 2(- 20) - 2 = - 42 - 80 + 40 - 2 = - 42 - 42 = - 42 ---------------checks
2x + 2 = 42 x = 20 20 and 22
2 because 22+42 = 20
20 percent of 42 = 8.4
86 - 42 = 44
If you mean points of (2, -3) and (4, 2) then the slope is 5/2 and the straight line equation is 2y = 5x-16
2 + 2 = 42 x 2 = 42/2 = 12 - 2 = 02^2 = 42! = 22 mod 2 = 02√2 = 1.41421356
The alpha decay of calcium-42 results in the emission of an alpha particle (helium nucleus) from the nucleus. The equation for this decay is: ( \require{cancel} \require{mhchem} \ce{^{42}{20}Ca -> ^{4}{2}He + ^{38}_{18}Ar} )
7x=42 x=42/7 or, x=6
42 is 20% of 210