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The equation is:

x3 - 4x2i - 9xi2+ 36i3 = 0

Note: The ' i ' must be an ordinary constant, and can't be sqrt(-1).

If it were sqrt(-1), then -4i would also be a root of the equation.

Imaginary or complex roots always occur in conjugate pairs.

If -4i is also a root of the equation and the questioner just forgot to include it,

then ' i ' can be sqrt(-1), and the equation can be

x4 + 25x2 + 144 = 0

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15y ago

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Q: What is the equation for whose roots are 4i -3i and 3i?
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