The equation is:
x3 - 4x2i - 9xi2+ 36i3 = 0
Note: The ' i ' must be an ordinary constant, and can't be sqrt(-1).
If it were sqrt(-1), then -4i would also be a root of the equation.
Imaginary or complex roots always occur in conjugate pairs.
If -4i is also a root of the equation and the questioner just forgot to include it,
then ' i ' can be sqrt(-1), and the equation can be
x4 + 25x2 + 144 = 0
Chat with our AI personalities
2i
Yes. Consider, if you can factor complex numbers, then logically, you should be able to take two complex numbers, multiply them together, and get a third. That can indeed be done. For example: (4i + 7)(3i + 2) = -12 + 8i + 21i + 14 = 29i + 2 Therefore, the complex number 29i + 2 must be divisible by 4i + 7 and 3i + 2.
It is a linear equation in a single variable, i. i = -27.5
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
A quadratic equation in standard form is based on the model: ax2 + bx + c = 0 a, b, and c are called the coefficients. "Real coefficients" simply means that a, b, and c are real numbers (as opposed to complex numbers). For example: 5x2 - 3x +2 = 0 ... has real coefficients, while (3-2i)x2 + (-2 + 4i)x + (4 + 3i) = 0 does not.