0
The equation is:
x3 - 4x2i - 9xi2+ 36i3 = 0
Note: The ' i ' must be an ordinary constant, and can't be sqrt(-1).
If it were sqrt(-1), then -4i would also be a root of the equation.
Imaginary or complex roots always occur in conjugate pairs.
If -4i is also a root of the equation and the questioner just forgot to include it,
then ' i ' can be sqrt(-1), and the equation can be
x4 + 25x2 + 144 = 0
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Find 2 square roots of 4i?
2i
Can you factor complex numbers?
Yes. Consider, if you can factor complex numbers, then logically, you should be able to take two complex numbers, multiply them together, and get a third. That can indeed be done. For example: (4i + 7)(3i + 2) = -12 + 8i + 21i + 14 = 29i + 2 Therefore, the complex number 29i + 2 must be divisible by 4i + 7 and 3i + 2.
What is 4i plus 55 equal to 2i?
It is a linear equation in a single variable, i. i = -27.5
2 plus 4i - 7 plus 4i?
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
What is a quadratic equation with real coefficents?
A quadratic equation in standard form is based on the model: ax2 + bx + c = 0 a, b, and c are called the coefficients. "Real coefficients" simply means that a, b, and c are real numbers (as opposed to complex numbers). For example: 5x2 - 3x +2 = 0 ... has real coefficients, while (3-2i)x2 + (-2 + 4i)x + (4 + 3i) = 0 does not.
What is conjugate of 4i open bracket -2 -3i close bracket?
4i(-2 -3i) = 4i×-2 - 4i×-3i = -8i -12i² = -8i + 12 = 12 -8i → the conjugate is 12 + 8i
Plot the number in a complex plane -1-3i?
2
What is the sum of (7 plus 3i) plus (8 plus 9i)?
(7 + 3i) + (8 + 9i) = (7 + 8) + (3i + 9i) = (7 + 8) + (3 + 9)i = 15 + 12i Which can also be written as: 15 + 12i = 3(5 + 4i).
Find 2 square roots of 4i?
2i
What is the product of these complex numbers (3-4i)(1-i)?
(3-4i)(1-i) = (3x1) + (3 x -i) + (-4i x 1) + ( -4i x -i) = 3 - 3i -4i -4 = -1 - 7i
What is the square root of -2?
2ii stands for imaginary, and any negative number's square root is an i number- i, 2i, 3i, 4i, etc.
How do you simplify the expression 3i x -4i?
7
Can you factor complex numbers?
Yes. Consider, if you can factor complex numbers, then logically, you should be able to take two complex numbers, multiply them together, and get a third. That can indeed be done. For example: (4i + 7)(3i + 2) = -12 + 8i + 21i + 14 = 29i + 2 Therefore, the complex number 29i + 2 must be divisible by 4i + 7 and 3i + 2.
Find the complex fourth root of 256i Express your answer in a plus bi form?
The four roots of 4√256 are {4, -4, 4i, and -4i}. Note that two of them are real numbers and the other two are pure imaginary, therefore 0 + 4i is the same as just 4i
How do you simplify 4i 3i?
Assume we have the product of these terms. Multiply these terms altogether to get 12i². Make note that i = √-1, i² = -1, i³ = -i and i⁴ = 1. Then, 12i² = 12(-1) = -12. That is the answer to the question.
What is 4i plus 55 equal to 2i?
It is a linear equation in a single variable, i. i = -27.5
What is the firing order for a 1991 Nissan truck?
STARTING FROM TOP AND GOING COUNTER CLOCKWISE: 2I, 4E, 1I 2E 3I 1E 4I 3E e FOR EXHAUST AND I FOR INTAKE
