Best Answer

The equation is:

x3 - 4x2i - 9xi2+ 36i3 = 0

Note: The ' i ' must be an ordinary constant, and can't be sqrt(-1).

If it were sqrt(-1), then -4i would also be a root of the equation.

Imaginary or complex roots always occur in conjugate pairs.

If -4i is also a root of the equation and the questioner just forgot to include it,

then ' i ' can be sqrt(-1), and the equation can be

x4 + 25x2 + 144 = 0

Q: What is the equation for whose roots are 4i -3i and 3i?

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2i

Yes. Consider, if you can factor complex numbers, then logically, you should be able to take two complex numbers, multiply them together, and get a third. That can indeed be done. For example: (4i + 7)(3i + 2) = -12 + 8i + 21i + 14 = 29i + 2 Therefore, the complex number 29i + 2 must be divisible by 4i + 7 and 3i + 2.

It is a linear equation in a single variable, i. i = -27.5

(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i

A quadratic equation in standard form is based on the model: ax2 + bx + c = 0 a, b, and c are called the coefficients. "Real coefficients" simply means that a, b, and c are real numbers (as opposed to complex numbers). For example: 5x2 - 3x +2 = 0 ... has real coefficients, while (3-2i)x2 + (-2 + 4i)x + (4 + 3i) = 0 does not.

Related questions

4i(-2 -3i) = 4i×-2 - 4i×-3i = -8i -12i² = -8i + 12 = 12 -8i → the conjugate is 12 + 8i

2

(7 + 3i) + (8 + 9i) = (7 + 8) + (3i + 9i) = (7 + 8) + (3 + 9)i = 15 + 12i Which can also be written as: 15 + 12i = 3(5 + 4i).

2i

(3-4i)(1-i) = (3x1) + (3 x -i) + (-4i x 1) + ( -4i x -i) = 3 - 3i -4i -4 = -1 - 7i

2ii stands for imaginary, and any negative number's square root is an i number- i, 2i, 3i, 4i, etc.

7

Yes. Consider, if you can factor complex numbers, then logically, you should be able to take two complex numbers, multiply them together, and get a third. That can indeed be done. For example: (4i + 7)(3i + 2) = -12 + 8i + 21i + 14 = 29i + 2 Therefore, the complex number 29i + 2 must be divisible by 4i + 7 and 3i + 2.

The four roots of 4âˆš256 are {4, -4, 4i, and -4i}. Note that two of them are real numbers and the other two are pure imaginary, therefore 0 + 4i is the same as just 4i

Assume we have the product of these terms. Multiply these terms altogether to get 12i². Make note that i = √-1, i² = -1, i³ = -i and i⁴ = 1. Then, 12i² = 12(-1) = -12. That is the answer to the question.

It is a linear equation in a single variable, i. i = -27.5

STARTING FROM TOP AND GOING COUNTER CLOCKWISE: 2I, 4E, 1I 2E 3I 1E 4I 3E e FOR EXHAUST AND I FOR INTAKE