The coordinates of the x intercept for the equation y equals x plus 1 is (x=-1, y=0).
If the equation is: y = -x then the slope is -1 and there is no y intercept
The line with equation crosses the y-axis at (0, 0), so the y-intercept is 0. While the line with equation x = 1 does not cross the y-axis at all (it is parallel to it), so it has no y-intercept.
Are you sure the directions don't have "solve the equation as x=___ and y=___"
It is a straight line equation.
The coordinates of the x intercept for the equation y equals x plus 1 is (x=-1, y=0).
If the equation is: y = -x then the slope is -1 and there is no y intercept
X-y=1
1
the y-1 is a minus .
The line with equation crosses the y-axis at (0, 0), so the y-intercept is 0. While the line with equation x = 1 does not cross the y-axis at all (it is parallel to it), so it has no y-intercept.
Are you sure the directions don't have "solve the equation as x=___ and y=___"
It is a straight line equation.
equation1: y+1 = x => y = x-1 equation 2: y = x2-6x++5 If, x2-6x+5 = x-1 then, x2-7x+6 = 0, solving this quadratic equation, x = 1 or x = 6 Substituting into equation 1: when x = 1, y = 0 and when x = 6, y = 5 Therefore the solutions are: x = 1, y = 0 and x = 6, y = 5
The equation is y=x(x+1)(x-2)2
y=4 x+y=5 so it wud be:::::: x+4=5 solve it from there by doing 1 step equation :)
x = 4 and y = 7