equation1: y+1 = x => y = x-1
equation 2: y = x2-6x++5
If, x2-6x+5 = x-1 then, x2-7x+6 = 0, solving this quadratic equation, x = 1 or x = 6
Substituting into equation 1: when x = 1, y = 0 and when x = 6, y = 5
Therefore the solutions are: x = 1, y = 0 and x = 6, y = 5
The solutions are: x = 4, y = 2 and x = -4, y = -2
1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)
There's an equals missing...
They are: (3, 1) and (-11/5, -8/5)
No. It's a quadratic equation, and it has two solutions.
The quadratic equation will have two solutions.
The solutions are: x = 4, y = 2 and x = -4, y = -2
1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)
There's an equals missing...
They are: (3, 1) and (-11/5, -8/5)
No. It's a quadratic equation, and it has two solutions.
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
The solutions to the quadratic equation are: x = -1 and x = 6
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
It is a simultaneous equation and when solved its solutions are x = 71/26 and y = 50/13
no
Simultaneous suggests at least two equations.