To find the equation of the line in point-slope form that passes through the points (-2, -2) and (-5, -3), we first need to calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{-3 - (-2)}{-5 - (-2)} = \frac{-1}{-3} = \frac{1}{3} ). Using point-slope form ( y - y_1 = m(x - x_1) ) with point (-2, -2), the equation becomes ( y + 2 = \frac{1}{3}(x + 2) ).
It is: y = 5x+6
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
That will depend on the value of the slope which has not been given.
To write the equation of a line with a slope of 5 that passes through the point (1, 3), we can use the point-slope form of the equation, which is (y - y_1 = m(x - x_1)). Here, (m) is the slope, and ((x_1, y_1)) is the point. Substituting the values, we get (y - 3 = 5(x - 1)). Simplifying this, the equation becomes (y = 5x - 2).
30
If the slope is undefined, it is a vertical line. Therefore the equation is x=2.
If you mean a point of (-1, 4) and a slope of -3 then the equation is y = -3x+1
Slope: -35 passing through (-5, -1) Equation: y = -35x-176
It is: y = 5x+6
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
If you mean passing through (1, 2) with a slope of -3 then it is y = -3x+5
That will depend on the value of the slope which has not been given.
To write the equation of a line with a slope of 5 that passes through the point (1, 3), we can use the point-slope form of the equation, which is (y - y_1 = m(x - x_1)). Here, (m) is the slope, and ((x_1, y_1)) is the point. Substituting the values, we get (y - 3 = 5(x - 1)). Simplifying this, the equation becomes (y = 5x - 2).
7
30
If the point is (-6, 3) and the slope is 2 then the equation is: y = 2x+15
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63