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If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
y = x - 3The graph is a straight line, passing through the point [ y = -3 ] on the y-axis,and having a slope of [ 1 ].
The general equation of the line is y = 3x + c. Having only one coordinate (21) of a point on this line is not enough to evaluate c.
It is the equation of a line passing through the point (0, 1/3) and with slope 4/3
It is: y = 5x+6
If you mean a point of (-1, 4) and a slope of -3 then the equation is y = -3x+1
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
y = x - 3The graph is a straight line, passing through the point [ y = -3 ] on the y-axis,and having a slope of [ 1 ].
If the slope is undefined, it is a vertical line. Therefore the equation is x=2.
The general equation of the line is y = 3x + c. Having only one coordinate (21) of a point on this line is not enough to evaluate c.
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It is the equation of a line passing through the point (0, 1/3) and with slope 4/3
If you mean passing through (1, 2) with a slope of -3 then it is y = -3x+5
It is: y = 5x+6
The equation of a vertical line passing through the point (-4,0) is x = -4. Since all points on a vertical line have the same x-coordinate, the equation is simply x = -4.
Use the point slope form. Y - Y1 = m(X - X1) Y - 11 = -3[X - (-3)] Y - 11 = -3X + 9 Y = -3X + 20
y=5