y = x/4 - 1
The straight line equation is: y = -4x+1
-3
The equation of a line can be expressed in the slope-intercept form, which is ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope of -3 and a y-intercept of 4, the equation of the line is ( y = -3x + 4 ).
This is the equation of a line in which the slope is 1 and the y-intercept is -4.
-4
The straight line equation is: y = -4x+1
-3
y = 1/3x-4 in slope intercept form
The equation of a line can be expressed in the slope-intercept form, which is ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Given a slope of -3 and a y-intercept of 4, the equation of the line is ( y = -3x + 4 ).
This is the equation of a line in which the slope is 1 and the y-intercept is -4.
the slope of a line is 9/5 the y intercept is -4, express the equation of the line in point slope form
The equation of a line written in slope intercept form has the form of y = mx + b. In this form, m is the slope of the line and b is the y intercept.
-4
The straight line equation works out as y = 3x+4 whereas 4 is the y intercept
The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. So we have y = mx + b (replace m with 4, and b with 1) y = 4x + 1
y=-x+4
-12