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Q: What is the equation of a line that has a y-intercept of -4 and a slope of 1.5?

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Rewriting the equation 3x + y = 15 gives y = 15 - 3xThe slope of this and any parallel line is the x multiple, which in this case is -3

36x-9y = 15 -9y = -36x+15 y = 4x-5/3 in slope intercept form

3X + 5Y = 155Y = -3X + 15Y = (-3/5)X + 3The slope of this line is -3/5.The slope of a line perpendicular to it is 5/3.

What is the equation of the line containing the points (5, 2), (10, 4), and (15, 6)?y = (2/5)x

Points: (-2, 4) and (-4, 8) Midpoint: (-3, 6) Slope: -2 Perpendicular slope: 1/2 or 0.5 Perpendicular bisector equation: y-6 = 0.5(x--3) meaning y = 0.5x+7.5

Related questions

Without the inclusion of an equality sign and not knowing the plus or minus values of the given terms it can't be considered to be a straight line equation

The slope of the line that represents the graph of that equation is 15.

15

If the point is (-6, 3) and the slope is 2 then the equation is: y = 2x+15

If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90

Equation of given line: 3x + y = 15 or y = -3x + 15 Slope of given line = coefficient of x = -3 Slope of perperndicular = -1/(slope of given line) = -1 / (-3) = 1/3

-5

Rewriting the equation 3x + y = 15 gives y = 15 - 3xThe slope of this and any parallel line is the x multiple, which in this case is -3

If the point is (6, 3) and the slope is -1/3 then the equation works out as 3y = -x+15

this is an equation of a line. it has a slope of 4/3 and a y-intercept of 5

I'm assuming here that this line is a straight line. If so, it has the general equation y=mx+c (where m= the gradient/slope and c is the intercept). Substituting in the values provided in the question, we yield; 15= (9x9)+c We then solve and rearrange; 15=81+c 15-81=c -66=c. Therefore, the slope intercept is -66

Slope: 2/3 Point: (9, 11) Equation: 3y = 2x+15

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