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What is the Cartesian equation of a circle whose end points of its diameter are at 10 -4 and 2 2?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
What is the equation for the line passing through the points of 2 2 and 4 -3 on the Cartesian plane?
It is: y = -2.5x+7
What is the equation of the line segment whose end points are at 2 3 and 11 13 on the Cartesian plane showing work?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9y = 10x+7
What are coordinates for -4x plus 9y equals 0?
-4x + 9y = 0 is the equation of a line in the Cartesian plane and the coordinates of any of the infinite number of points on that line will satisfy the equation.
When you use the distance formula you are building a right triangle whose connects two given points.?
The distance formula, given by ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ), calculates the straight-line distance between two points ((x_1, y_1)) and ((x_2, y_2)) in a Cartesian plane. This formula effectively derives from the Pythagorean theorem, where the horizontal and vertical differences between the points form the two legs of a right triangle. The hypotenuse of this triangle represents the distance between the two points. Thus, using the distance formula geometrically relates to constructing a right triangle connecting the given points.
What is the Cartesian equation of a circle whose end points of its diameter are at 10 -4 and 2 2?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
What is the equation of the line whose end points are 5 2 and 3 2 on the Cartesian plane?
The equation is y = 2
What is the equation and its distance from origin that meets the line joining the points 13 17 and 19 23 at its midpoint on the Cartesian plane showing work?
Points: (13, 17) and (19, 23) Midpoint: (16, 20) Slope of required equation: 5/4 Its equation: 4y = 5x or as y = 1.25x Its distance from (0, 0) to (16, 20) = 4 times sq rt 41
What is the equation of a circle whose diameter end points are at 10 -4 and 2 2 on the Cartesian plane?
End points: (10, -4) and (2, 2) Midpoint: (6, -1) Distance from (6, -1) to (10, -4) = 5 Distance from (6, -1) to (2, 2) = 5 Equation of the circle: (x-6)^2 +(y+1)^2 = 25
What is the equation for the line passing through the points of 2 2 and 4 -3 on the Cartesian plane?
It is: y = -2.5x+7
What is the equation of the line segment whose end points are at 2 3 and 11 13 on the Cartesian plane showing work?
Points: (2, 3) and (11, 13) Slope: 10/9 Equation: 9y = 10x+7
What are coordinates for -4x plus 9y equals 0?
-4x + 9y = 0 is the equation of a line in the Cartesian plane and the coordinates of any of the infinite number of points on that line will satisfy the equation.
When you use the distance formula you are building a right triangle whose connects two given points.?
The distance formula, given by ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ), calculates the straight-line distance between two points ((x_1, y_1)) and ((x_2, y_2)) in a Cartesian plane. This formula effectively derives from the Pythagorean theorem, where the horizontal and vertical differences between the points form the two legs of a right triangle. The hypotenuse of this triangle represents the distance between the two points. Thus, using the distance formula geometrically relates to constructing a right triangle connecting the given points.
What is used to locate points x y in the coordinate plane?
It is the straight line equation that can be used to locate coordinates of x and y on the Cartesian plane
What is the answer for this question in the Cartesian plane (54)(63)?
If you mean points of (5, 4) and (6, 3) then the slope is -1 and equation is y=-x+9
What figure do you get if you join two points in cartesian plane?
You get a curve. If you join them along the shortest [Euclidean] distance between them, you get a straight line.
What type of graph does an equation of the form x equals a where a is any real number have and why?
It is a horizontal line in the Cartesian plane, or a vertical line in the complex plane. The reason is that these points satisfy the equation while no others do.
