To find the equation of the line that passes through the point (-3, 1) with a slope of ( \frac{2}{3} ), you can use the point-slope form of the linear equation: ( y - y_1 = m(x - x_1) ). Substituting the point (-3, 1) and the slope ( \frac{2}{3} ) into the equation gives:
[ y - 1 = \frac{2}{3}(x + 3). ]
This simplifies to ( y = \frac{2}{3}x + 3 ).
To write the point-slope equation of a line that passes through the point (5, 5), you need a slope (m) as well. The point-slope form is given by the equation ( y - y_1 = m(x - x_1) ). If the slope is not provided, you can express the equation generically as ( y - 5 = m(x - 5) ), where ( m ) is the slope of the line. If you have a specific slope, you can substitute it into the equation.
Point: (2, 17)Slope: 7Equation: y = 2x+13
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
If you mean a point of: (-4, 7) and a slope of 4 Then the equation works out as: y = 4x+23
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
33
Point: (1, 4) Slope: -3 Equation: y = -3x+7
Point: (2, 17)Slope: 7Equation: y = 2x+13
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10
If you mean a point of: (-4, 7) and a slope of 4 Then the equation works out as: y = 4x+23
The equation is: y = 4x-22
Slope=8 point=(-7,3)
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
y = 7
y = 5