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The ' 1 ' in that equation is the radius.
It is (x + 1)2 + (y - 3)2 = 42
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
Length of diameter:length of radius = 2:1
End points: (10, -4) and (2, 2) Midpoint: (6, -1) which is the centre of the circle Distance from (6, -1) to any of its end points = 5 which is the radius Therefore the Cartesian equation is: (x-6)^2 +(y+1)^2 = 25
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
Equation: (x+1)^2 +(y-3)^2 = 16
The ' 1 ' in that equation is the radius.
It is (x + 1)2 + (y - 3)2 = 42
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
Equation of the circle: (x+1)^2 +(y+3)^2 = 25
The relation between focal length (f), radius of curvature (R), and the focal point of a spherical mirror can be described by the mirror equation: 1/f = 1/R + 1/R'. The focal length is half the radius of curvature, so f = R/2.
Length of diameter:length of radius = 2:1
The focal length of a lens is related to its radius of curvature and the index of refraction by the lensmaker's equation: [\frac{1}{f} = (n-1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)] Given the radius of curvature (R = 0.70 , m) and the index of refraction (n = 1.8), you can calculate the focal length.
(x-1)^2 + (y-2)^2 = 3^2
The radius is 1/2 of the diameter. A diameter of 10 has a radius of 5.