If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
Points: (8, 2) and (0, 0) Slope: 1/4 or 0.25 Equation: y = 0.25x
radius of 31 inches
The circumference of a circle with a radius of 31 meters is about 194.8 meters.
To find the width of the rectangle, we can use the formula for the perimeter, which is ( P = 2 \times (length + width) ). Given the perimeter is 80 cm and the length is 31 cm, we can set up the equation: ( 80 = 2 \times (31 + width) ). Simplifying this gives ( 40 = 31 + width ), so the width is ( 40 - 31 = 9 ) cm. Thus, the width of the rectangle is 9 cm.
The diameter is 31 times 2 = 62 miles
A circle with a radius of 31 cm has an area of 3019.07 square cm.
A score of 31 earns 2 points in cribbage.
The equation 31 time 744 equals 23,064. All you have to do is add up 744 31 times.
If: 31x = 31 then x = 1
31 pm This is not correct the best answer for helium would be 0.0 or n/a Helium also has no covalent radius. The atomic volume of helium is 31.8
The covalent radius of francium is 260 pm.The covalent radius of hydrogen is 31 pm.
31/3.1 ie 10