To find the equation for the statement "the quotient of a number and 7 is 13," we can let the number be represented by the variable ( x ). The equation can be written as ( \frac{x}{7} = 13 ). To solve for ( x ), multiply both sides by 7, resulting in ( x = 13 \times 7 ), which simplifies to ( x = 91 ).
Let the number be represented by ( x ). The algebraic equation for the quotient of five times this number and 7 being no more than 10 can be expressed as: [ \frac{5x}{7} \leq 10 ]
x/n + 7 = 68 or x/n = 61 or x = 61n
-227
n - 13 = 7
The equation can be written as -7x - 4 = 13 - 6x, where "x" represents the unknown number.
Let the number be represented by ( x ). The algebraic equation for the quotient of five times this number and 7 being no more than 10 can be expressed as: [ \frac{5x}{7} \leq 10 ]
It is the equation: n/(-5) + 1 <= 7
It is the equation: v = t/7 + 12
x/n + 7 = 68 or x/n = 61 or x = 61n
y = 5(x+7) = 5x + 35
-227
n - 13 = 7
-241 * * * * * Actually, the answer is 13*(-18) + 7 = -227 The remainder is ALWAYS positive. Thus -227/13 = (-234+7)/13 = -234/13 + 7/13 = -18 + 7/13
It is the equation: x/9 + 7 = 5
It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15It is an equation which states that 3*(n/7) = 15
91
The equation can be written as -7x - 4 = 13 - 6x, where "x" represents the unknown number.