y = 5(x+7) = 5x + 35
5*B = 95
The algebraic expression for "twice a number" would be 2x, where x represents the unknown number. To find the quotient of 2x and 6, you would divide 2x by 6, which simplifies to (2x) / 6. This can be further simplified to x / 3, which represents the final quotient of twice a number and 6 in algebraic expression.
the quotient of twice a number and six is.... 2x/6 four less than three times the same number is .... 3x-4 So the equation would be 2x/6=3x-4
let x=the number 87-3*(x)>165
4x
6x/23
5*B = 95
n + 2n = 3n
The algebraic expression for "twice a number" would be 2x, where x represents the unknown number. To find the quotient of 2x and 6, you would divide 2x by 6, which simplifies to (2x) / 6. This can be further simplified to x / 3, which represents the final quotient of twice a number and 6 in algebraic expression.
2x - 16 = 3x/18
Let's represent the number as (x). The phrase "Eight less than five times a number" can be translated to (5x - 8), and "is seven more than the number" can be translated to (x + 7). Therefore, the algebraic equation representing the given phrase is (5x - 8 = x + 7).
5
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To find the equation for the statement "the quotient of a number and 7 is 13," we can let the number be represented by the variable ( x ). The equation can be written as ( \frac{x}{7} = 13 ). To solve for ( x ), multiply both sides by 7, resulting in ( x = 13 \times 7 ), which simplifies to ( x = 91 ).
Write the following as an algebraic expression using x as the variable: The sum of a number and -8
the quotient of twice a number and six is.... 2x/6 four less than three times the same number is .... 3x-4 So the equation would be 2x/6=3x-4
The quotient.