It works out as: 2x+y-16 = 0
bisecting
perpendicular bisector
When the two endpoints of a line segment are folded to line up, a perpendicular bisector of the segment is constructed. This line divides the original segment into two equal parts at a right angle. The point where the endpoints meet forms a new point along the bisector, effectively bisecting the segment into two congruent segments.
The final step in bisecting a line segment is to draw a line through the two intersection points of the arcs created from each endpoint. This line should intersect the original segment at its midpoint, effectively dividing the segment into two equal parts. You can then label this midpoint if necessary.
. . . is the segment perpendicular to the line.
a secant
bisecting
perpendicular bisector
It's called a perpendicular bisector of the line segment.
When the two endpoints of a line segment are folded to line up, a perpendicular bisector of the segment is constructed. This line divides the original segment into two equal parts at a right angle. The point where the endpoints meet forms a new point along the bisector, effectively bisecting the segment into two congruent segments.
Perpendicular Bisector
The perpendicular bisector of a line segment AB is the straight line perpendicular to AB through the midpoint of AB.
The final step in bisecting a line segment is to draw a line through the two intersection points of the arcs created from each endpoint. This line should intersect the original segment at its midpoint, effectively dividing the segment into two equal parts. You can then label this midpoint if necessary.
Endpoints: (2, 9) and (9, 2) Midpoint: (5.5, 5.5) Slope of line segment: -1 Perpendicular slope: 1 Perpendicular bisector equation: y-5.5 = 1(x-5.5) => y = x
Line segment
. . . is the segment perpendicular to the line.
No, a segment is not necessarily perpendicular. A segment is simply a straight line connecting two points. A perpendicular segment would be a segment that forms a right angle with another segment or line.