twice the area of the triangle with the same base an height.
The parallelogram has twice the area of the triangle if their bases are the same and their heights are the same. Area triangle = 1/2 base x height. Area parallelogram = base x height.
It is base x height for the parallelogram. That is twice the area of a triangle which is: 1/2 base x height. (Base and height being the same for both cases).
A triangle and a parallelogram can have the same area if the base and height of the triangle are proportional to the base and height of the parallelogram. Specifically, the area of a triangle is given by ( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} ), while the area of a parallelogram is ( \text{Area} = \text{base} \times \text{height} ). Therefore, if the base of the parallelogram is twice the base of the triangle and they share the same height, their areas will be equal.
Let the length be ( l ) and the height be ( h = 2l ). The perimeter ( P ) of a rectangle is given by the formula ( P = 2(l + h) ). Substituting ( h ) into the perimeter equation, we have ( 210 = 2(l + 2l) = 2(3l) ), which simplifies to ( 210 = 6l ). Solving for ( l ), we find ( l = 35 ) inches, and thus the height ( h = 2l = 70 ) inches.
twice the area of the triangle with the same base an height.
The parallelogram has twice the area of the triangle if their bases are the same and their heights are the same. Area triangle = 1/2 base x height. Area parallelogram = base x height.
It is base x height for the parallelogram. That is twice the area of a triangle which is: 1/2 base x height. (Base and height being the same for both cases).
A triangle and a parallelogram can have the same area if the base and height of the triangle are proportional to the base and height of the parallelogram. Specifically, the area of a triangle is given by ( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} ), while the area of a parallelogram is ( \text{Area} = \text{base} \times \text{height} ). Therefore, if the base of the parallelogram is twice the base of the triangle and they share the same height, their areas will be equal.
Let the length be ( l ) and the height be ( h = 2l ). The perimeter ( P ) of a rectangle is given by the formula ( P = 2(l + h) ). Substituting ( h ) into the perimeter equation, we have ( 210 = 2(l + 2l) = 2(3l) ), which simplifies to ( 210 = 6l ). Solving for ( l ), we find ( l = 35 ) inches, and thus the height ( h = 2l = 70 ) inches.
No!
one
if you are given the circle's "height" then that is the diameter. the diameter is twice the length of the radius, so divide the height by two and you will get the radius.
L = 2w + 2
Let the length of the rectangle be ( L ). According to the problem, the length is 3 meters less than twice its length, which can be expressed as ( L = 2L - 3 ). Rearranging this equation gives ( L - 2L = -3 ), or ( -L = -3 ). Thus, ( L = 3 ) meters.
Just spell out your sentence mathematically: 3 more than => 3 +, twice => 2 *, then you have your variable of the base. Put it all together, and h = 3+2b.
2,058/2,058= remander if 0 times 3 with the 0 and that will give you 0 and then you try to find the height of the length? The Answer is Fourteen or 14 cm for the height The Answer is twenty-one or 21 for the length