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x = cx = aa+1 If x = cx, then c = 1 aa = a2 if a2 + 1 = x, then a2 = x-1 short of parametrization, this is the answer for this equation, but if you doing advanced maths, then let x= t (teR) a2 = -1 +t (teR)
14-a=714= 7+aa= 7
It depends on the shape in question. Clearly it is not a straightforward shape since AA - conventionally, the distance of the point A from itself - is 33 rather than 0.
p represents the square root of the frequency of the homozygous genotype AA.
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
+/- 11
The direction of a chemical reaction is determined by the free energy change (ΔG) of the reaction. If ΔG is negative, the reaction is spontaneous in the forward direction; if ΔG is positive, the reaction is non-spontaneous in the forward direction; and if ΔG is zero, the reaction is at equilibrium. This is determined by the difference in free energy between the products and reactants.
x = cx = aa+1 If x = cx, then c = 1 aa = a2 if a2 + 1 = x, then a2 = x-1 short of parametrization, this is the answer for this equation, but if you doing advanced maths, then let x= t (teR) a2 = -1 +t (teR)
AA
Heterozygotes. If AA X AA, or AA X AA, is all the mating allowed, then Aa will lose frequency in the population.
Molarity of products divided by reactants Keq=(products)/(reactants)
aa+2 is an expression, not an equation. An expression has no answer.
The Hardy-Weinberg Equilibrium equation: p2 + 2pq + q2 = 1 p is frequency of dominant allele A q is frequency of recessive allele a p + q always equals 1 pp or p2 is probability of AA occurring qq or q2 is probability of AA occurring 2pq is probability of Aa occurring (pq is probability of Aa, qp is probability of aA, so 2pq is probability of all heterozygotes Aa) These add up to 1 because they represent all possibilities. The frequency of the homozygous recessive genotype
Yes an No. You can have blood type AB in following situations: AO+BO AO+BB AA+BO AA+BB AB+BB AA+AB AB+AB So there's more possible ways to get type AB other than the combination of ABs.
In the Hardy-Weinberg equation, p2 represents the frequency of the homozygous dominant genotype in a population for a specific gene. It represents the proportion of individuals in the population that have two copies of the dominant allele.
aa+bb=cbc The a would be a 9, the b would be a 2 and the c would be a 1
14-a=714= 7+aa= 7