solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
1.5848931924611135 to the power of five equals 10.
e^x - 2 = 8 e^x = 10 So x = ln(10) = 1/log10(e)
Molarity of hydrogen solution equals 2.3 X 10^-4 -log(2.3 X 10^-4) = 3.6 pH
your solution is x=10. solving algebra means you define what the variable means. 10=x is already there.
solution with [OH-] = 2.5 x 10-9 , A solution with [H+] = 1.2 x 10-4, A solution with pH = 4.5
10 to the 5th power
1.5848931924611135 to the power of five equals 10.
The solution is supersaturated
the solution is supersaturated
e^x - 2 = 8 e^x = 10 So x = ln(10) = 1/log10(e)
The solution is unsaturated.
-5
a * 0.1 = 10 * 0.1 = 1.0
A + 10 = 55If you mean the solution for A, A = 45.
Molarity of hydrogen solution equals 2.3 X 10^-4 -log(2.3 X 10^-4) = 3.6 pH
your solution is x=10. solving algebra means you define what the variable means. 10=x is already there.