...eight interior and exterior angles. ANGLES
If the polygon has n sides, each exterior angle is 360/n degrees.The interior angle is 180 less exterior angle.
Interior angles are angles formed by two adjacent sides on the inside of a polygon. An exterior angle is the supplement of the interior angle.
Not possible in this Universe. Smallest regular polygon is a triangle when interior angles are 60o. If exterior angles are 30o the polygon has 360/30 ie 12 sides.
Exterior angle 12 degrees Interior angle 168 degrees
Interior angles 178 so exterior angles 2. Number of sides of any regular polygon = 360/exterior angle You polygon has 180 sides. Bet you're glad you didn't have to sketch it!
Four sides
...eight interior and exterior angles. ANGLES
If interior angles are 177o then exterior angles are 3o. Exterior angle times number of sides is always 360 so the polygon has 120 sides.
Exterior angles are 7.5 There are 48 sides.
The easiest way to solve this is to use the exterior angles of the polygon. The sum of an exterior angle and interior angle is 180o. Also the sum of all the exterior angles of a polygon is 360o. As the polygon is regular, all the interior angles are the same and all the exterior angles are the same. So, for an interior angle of 172o the exterior angle is 180-172 = 8o. The sum of all the exterior angles is 360o so how many 8o make up 360o? 360/8=45. Thus the polygon with interior angles of 172o has 45 sides.
4 such as a square
The sum of what of a 92 sided polygon? The lengths of the sides? The exterior angles? The interior angles?
If the polygon has n sides, each exterior angle is 360/n degrees.The interior angle is 180 less exterior angle.
Interior angles are angles formed by two adjacent sides on the inside of a polygon. An exterior angle is the supplement of the interior angle.
That's true if the interior angles are 108 degrees, but a regular polygon cannot have exterior angles of 108 degrees.
The sum of the exterior angles of all polygons equals to 360⁰.Since only the sum of the interior angles of all quadrilaterals equals to 360⁰, the polygon must have 4 sides.