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25y2 - 49w2 = (5y)2 - (7w)2 = (5y - 7w)(5y + 7w)
56w2 + 17w - 3 = 56w2 + 24w - 7w - 3 = 8w(7w + 3) - 1(7w + 3) = (7w + 3)(8w - 1)
224
8788654
509w
An "extraneous solution" is not a characteristic of an equation, but has to do with the methods used to solve it. Typically, if you square both sides of the equation, and solve the resulting equation, you might get additional solutions that are not part of the original equation. Just do this, and check each of the solutions, whether it satisfies the original equation. If one of them doesn't, it is an "extraneous" solution introduced by the squaring.
-63=7w
16
25y2 - 49w2 = (5y)2 - (7w)2 = (5y - 7w)(5y + 7w)
56w2 + 17w - 3 = 56w2 + 24w - 7w - 3 = 8w(7w + 3) - 1(7w + 3) = (7w + 3)(8w - 1)
127w = 847w/7 = 84/7w = 12
7w - 4w - 6w = (7 - 4 - 6)w = -3w
7w=122 122/7= 17.43 w=17.43
3w + 4e + 7w - e3 = 10w - e
(5y + 7w)(5y - 7w)
224
Ill assume you mean for an are of a rectangle. w will stand for width. So you know the equation for a rectangle is L*W, so if length is 7W, then the area is 7W*W=Area or 7W^2