The only common factor of those two terms is the number three, giving you:
3(x3 - 8y3)
2x 2x to the second
It is: (-3x-4)(x+2) when factored
(3x)^(2-4) = (3x)^-2 = (9x2)^-1 = 1/(9x2)
To find the product of (x+4) and (x^2-3x+2), you need to distribute each term in the first expression to each term in the second expression. This results in x*(x^2-3x+2) + 4*(x^2-3x+2). Simplifying further, you get x^3-3x^2+2x + 4x^2-12x+8. Combining like terms gives you the final answer: x^3+x^2-10x+8.