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The only common factor of those two terms is the number three, giving you:
3(x3 - 8y3)
(3x)^(2-4) = (3x)^-2 = (9x2)^-1 = 1/(9x2)
2x 2x to the second
It is: (-3x-4)(x+2) when factored
(x + 4)(x^2 + 3x + 2) = x^3 + 7x^2 + 14x + 8