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To find the product of (x+4) and (x^2-3x+2), you need to distribute each term in the first expression to each term in the second expression. This results in x*(x^2-3x+2) + 4*(x^2-3x+2). Simplifying further, you get x^3-3x^2+2x + 4x^2-12x+8. Combining like terms gives you the final answer: x^3+x^2-10x+8.
Oh, what a happy little question! To find the product of (x+4) and (x^2+3x+2), we need to distribute x+4 to each term in the second expression. This gives us x^3+3x^2+2x+4x^2+12x+8. Simplifying further, we get x^3+7x^2+14x+8. Just remember, there are no mistakes, just happy little accidents!
Alright, buckle up buttercup. To multiply these two binomials, you use the distributive property twice. First, multiply x by each term in the second binomial, then do the same with 4. Finally, combine like terms to simplify the expression. It's like a math dance, but with less rhythm and more numbers.
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What is x3 plus 4x2-3x-12 divided by x2-3?
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
What is 4x2 10x 6 factored?
The operators are missing, the possible factorisations are:4x2 + 10x + 6 = 2(2x + 3)(x + 1)4x2 - 10x + 6 = 2(2x - 3)(x - 1)4x2 + 10x - 6 = 2(2x - 1)(x + 3)4x2 - 10x - 6 = 2(2x + 1)(x - 3)
How do you do (3x 4)2?
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
What does 3x x equal?
3x^2
What is the value of 3x-x?
3x - x = x(3 - 1) = x(2) = 2x
What is the sum of 3x2 x 2 and x2 2x 1?
If the missing signs are all pluses, that's 4x2 + 3x + 3
What is x3 plus 4x2-3x-12 divided by x2-3?
(x3 + 4x2 - 3x - 12)/(x2 - 3) = x + 4(multiply x2 - 3 by x, and subtract the product from the dividend)1. x(x2 - 3) = x3 - 3x = x3 + 0x2 - 3x2. (x3 + 4x2 - 3x - 12) - (x3 + 0x2 - 3x) = x3 + 4x2 - 3x - 12 - x3 + 3x = 4x2 - 12(multiply x2 - 3 by 4, and subtract the product from 4x2 - 12)1. 4x(x - 3) = 4x2 - 12 = 4x2 - 122. (4x2 - 12) - (4x2 - 12) = 4x2 - 12 - 4x2 + 12 = 0(remainder)
What are the factors of 12x2-3x plus 6?
3(4x2 - x + 2)
Factor method solve 4x2 - 2x-12?
4x2 - 2x - 12= 2x2 - x - 6= 2x2 - 4x + 3x - 6= 2x(x - 2) + 3(x - 2)= (x - 2)(2x + 3)
What is linear in 4x2 3x - 6?
4x2 + 3x - 6 is a second degree polynomial. Since the polynomial function f(x) = 4x2 + 3x - 6 has 2 zeros, it has 2 linear factors. Since we cannot factor the given polynomial, let's find the two roots of the equation 4x2 + 3x - 6 = 0, which are the zeros of the function. 4x2 + 3x - 6 = 0 x2 + (3/4)x = 6/4 x2 + (3/4)x + (3/8)2 = 6/4 + 9/64 (x + 3/8)2 = 105/64 x + 3/8 = ± √(105/64) x = (-3 ± √105)/8 x = -(3 - √105)/8 or x = -(3 + √105)/8 Thus, the linear factorization of f(x) = 4[x + (3 - √105)/8][x + (3 + √105)/8].
What is 3x -3x plus 4x2 plus 8x?
3x-3x+4x^2+8x=4x^2+8x
Can anyone help me solve this equation. I have tried it but the answer I get is totally different to what's in the mark scheme 3x squared -2x plus 2-x squared equals 2?
sorry it wouldn't let me put brackets in. it should read 3x^2 -2x + (2-x)^2 = 2 3x2-2x+4-4x+x2=2 4x2-6x+4=2 4x2-6x+2=0 2(2x2-3x+1)=0 2(x-1)(2x-1)=0 x=1 or x=1/2
How do you solve -4x2 plus 5x plus 6 equals 0 by factoring?
-4x2 + 5x + 6 = 0 Multiply through by -1: 4x2 - 5x - 6 = 0 (I prefer the leading coefficient to be >0) 4x2 - 8x + 3x - 6 = 0 4x(x - 2) + 3(x - 2) = 0 (x - 2)(4x + 3) = 0 So x - 2 = 0 or 4x + 3 = 0 ie x = 2 or x = -3/4
Y equals 4X2 plus 3x plus 8?
y=4x2+3x+8
How do you factor out 36x4-8x3-28x2?
2 x 2 x 3 x 2 x 2 x 7 x 2 x 2 x 2 = 27 x 3 x 7 or 2688
What Is The Standard Form Of x squared-5 equals negative 4xsquared equals 3x?
The first equality is: x2 - 5 = -4x2 which gives 5x2 - 5 = 0 which is equivalent to x2 - 5 = 0 The second equality is: -4x2 = 3x which gives 4x2 + 3x = 0 The two results are inconsistent.
What is the orderd pair for 3x plus 4y 17?
X=3 y=2 (3x3) + (4x2) = 17 9 + 8 = 17
