the factor tree of 9 is 3 squared, or 3 x 3. 9 breaks down into 3 and 3.
It is: 2*3*5*5 = 150 or as 2*3*52 = 150
12 6,2 3,2,2 42 21,2 7,3,2 2 x 3 = 6, the GCF
144 12 12 4 3 4 3 2 2 2 2
As a product of its prime factors: 2*2*2*3*5 = 120
12*6 4*3*2*3
12 6,2 3,2,2 54 27,2 9,3,2 3,3,3,2 2 x 3 = 6, the GCF
12 ^ 6•2 ^ \ 2•3•2 =2x2x3
9 x 4 will not complete a factor tree, but both 9 x 4 and 12 x 3 will get to 2 x 2 x 3 x 3 which will.
3 is a prime number. Prime numbers don't have factor trees. The factors of 3 are 1 and 3.
That's a lot of extra work for this problem but here goes. 3 is already prime so it doesn't really have a factor tree or prime factorization. The prime factorization of 4 is 2 x 2 which looks like this in a factor tree.42,23 and 4 have no common prime factors, so the LCM is their product, 12
It is: 3*17 = 51
Here are factor trees for 12 and 42: 12 - 2 - 6 - 2 - 3 42 - 2 - 21 - 3 - 7 The leaves in 12's factor tree are: 2, 2, and 3. The leaves in 42's factor tree are: 2, 3, and 7. The longest common sub-sequence of the leaf lists is: 2, 3. Therefore, multiply 2 by 3 and we get that 6 is the gcf of 12 and 42.
Factor Tree of 612: ..........612 ............/ \ ........12 * 51 ......../ \ ......6 * 2 ...../ \ ...2 * 3 Prime factorization of 612 = 2 * 2 * 3 * 51
In the case of 27, there is only one possible factor tree - using the factors 3 and 9 as the first step. 27 3 x 9 3 x (3x3)
45 5, 9 5, 3, 3
Use a factor tree to break apart numbers.ie. 12...../ \....2 6....../ \.....2 3The prime factors of 12 are 2, 2, and 3.