(x - 3)(x - 2)
6x + 6v + 1 =6 (x + v) + 1
To express (6(2) + 6(3)) in factored form, first calculate the individual products: (6(2) = 12) and (6(3) = 18). Adding these gives (12 + 18 = 30). To factor this, notice that both terms share a common factor of 6: (6(2 + 3)). Thus, in factored form, it is (6(5)) since (2 + 3 = 5).
x2+x-6 = (x-2)(x+3) when factored
6x5(x2 - 6x + 3)
6 + 3u can be factored into 2(3 + u)
(x - 8)(x - 6)
6x + 6v + 1 =6 (x + v) + 1
x2+x-6 = (x-2)(x+3) when factored
6x2 + 5x - 6 is factored out to (2x + 3)(3x - 2).
6x5(x2 - 6x + 3)
6 + 3u can be factored into 2(3 + u)
I think so.r2 + 7r + 6 = [ (r+6) (r+1) ]
x^2 +7x+6 = (x+1)(x+6) when factored
It is: (x+1)(x+6) when factored
x2 + 5x + 6 = (x + 2)(x + 3)
6•2+6•3
3x2-39x-90 = (3x+6)(x-15) when factored