x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
i got 42 divided 7x
-x2 + x + 42= -x2 + 7x - 6x + 42= 7x - x2 + 42 - 6x= x(7 - x) + 6(7 - x)= (7 - x)(x + 6)
x2- 7x + 6 = 0 factor, (x-6)(x-1) = 0 x = 6 x = 1
It is: (x+1)(x+6) when factored
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
x2 + 7x + 6 = (x + 6) (x + 1)
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
i got 42 divided 7x
-x2 + x + 42= -x2 + 7x - 6x + 42= 7x - x2 + 42 - 6x= x(7 - x) + 6(7 - x)= (7 - x)(x + 6)
x2- 7x + 6 = 0 factor, (x-6)(x-1) = 0 x = 6 x = 1
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
It is: (x+1)(x+6) when factored
x2-7x+6 = (x-1)(x-6) when factored.
x2 - 7x + 6 = 0(x - 6)(x - 1) = 0x = 6, x = 1
This is not factorable. You would have to do the quadratic formula for this problem.
(x + 6)(x + 1) = 0 so x = either -1 or -6