What is the factorization of the trinomial below 7x2 plus 7x - 14?

Answer 1

To factor the trinomial (7x^2 + 7x - 14), first factor out the common factor of 7:

[ 7(x^2 + x - 2) ]

Next, we can factor the quadratic (x^2 + x - 2) into ((x + 2)(x - 1)).

Thus, the complete factorization of the original trinomial is:

[ 7(x + 2)(x - 1) ]