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Is this 7x2-5x plus 2 a monomial binomial or trinomial?
The term with the highest power(s) of the unknown variable(s) is 7x2. The power is 2 so the expression is a binomial.
How do you solve -9x plus 4 equals -50?
-9x + 4 = -50 -9x = -50 - 4 -9x = -54 -x = -6 x = 6.
-9x5 over the square root of x plus 4?
(-9x^2/√x) + 4= [-9x^2/x^(1/2)] + 4= (-9x^2)[x^(-1/2)] + 4= -9x^[2 + (-1/2)] + 4= -9x^(2 - 1/2) + 4= -9x^(3/2) + 4= -9√x^3 + 4= -9√[(x^2)(x)] + 4= -9x√x + 4Or,(-9x^2/√x) + 4= [(-9x^2)(√x)/(√x)(√x)] + 4= [(-9x^2)(√x)/√x^2] + 4= [-9(x)(x)(√x)/x] + 4 simplify x= -9x√x + 4
9x plus 4 equals x-7?
9x+4 =x-7 8x=-3 x=-3/8
What is x2 equals 9x-20?
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
What is the correct classification of 7x2 9x 4?
It is an algebraic expression of 3 terms
How do you simplify 7x2 - 9x - 10?
I suppose you mean, how do you factor it. 7x2 - 9x - 10 = (7x + 5)(x - 2).
7x2 - 9x - 10 factor completely?
(7x + 5)(x - 2)
What is the trinomial for 5x plus 4 9x plus 9?
(5x+4)(9x+9) FOIL First (5x*9x=45x**2) Outside (5x*9=45x) Inside (4*9x=36x) Last (4*9=36) 45x**2+45x+36x+36 45x**2+81x+36 9(5x**2+9x+4x)
81x2 - 72x plus 16 is a perfect square trinomial true or false?
If a trinomial is a perfect square, then the discriminant will equal 0. The discriminant is equal to B^2-4AC. The variables come from the standard form of a quadratic which is Ax^2+Bx+C In this problem, A=81, B=-72, and C=16 so the discriminant is: (-72)^2-4(81)(16)=5,184-5,184=0 so this is a perfect square trinomial. To factor, notice that 81=9^2 and 16=4^2, so 81x^2=(9x)^2. We can then factor the trinomial into (9x+4)(9x-4)
Is 3x plus 3x plus 3x a trinomial?
No. It is 9x, which is a monomial.
Is this 7x2-5x plus 2 a monomial binomial or trinomial?
The term with the highest power(s) of the unknown variable(s) is 7x2. The power is 2 so the expression is a binomial.
What is the factor trinomial 2x plus 7x plus 10?
10 + 9x
What is the trinomial (3x plus 9)(3x plus 2)?
9x+3
What is the factorization of the trinomial 2x squared plus 9x plus 9?
2x2+9x+9 = (2x+3)(x+3) when factored
How do you solve the quadratic equation 7x2-5x equals 0 by factoring?
if the x in "7x2" is variable x, then 7x(2)-5x=0 14x-5x=0 9x=0 x=0 if the x in "7x2" is a symbol for multiplication, then 7(2)-5x=0 14-5x=0 -5x= -14 5x=14 x= 14/5 x= 2 4/5 or, to factor it out... x(14-5)=0 x(9)=0 9x=0
Factor the trinomial x2 plus 9x plus 14?
(x+7)(x+2)
