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-x2 - 11x + 26

= -(x2 + 11x - 26)

= -(x2 - 2x + 13x - 26)

= -[ x(x - 2) + 13(x - 2) ]

= -(x + 13)(x - 2)

= (x + 13)(2 - x)

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Q: What is the factorization of this trinomial -x2 - 11x plus 26?
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What is the factorization of the trinomial -x2 - 11x 26?

-(x + 13)(x - 2)


What is the factorization of the trinomial x2 11x - 26?

Do you mean x2+11x-26 if so then it is (x-2)(x+13) when factored


What is the factorization of the trinomial -x2 11x 26?

Divide all terms by -1 so: x2-11x-26 = (x+2)(x-13) when factored


What is the factorization of the trinomial -x squared plus 11 x plus 26?

-x2 + 11x + 26 = -(x - 13)(x + 2) = (13 - x)(x + 2) = (x - 13)(-x - 2)


What is the factorization of the trinomial below -x2-11x plus 26?

-x2 - 11x + 26= -x2 - 13x + 2x + 26= (2x - x2) + (26 - 13x)= x(2 - x) + 13(2 - x)= (2 - x)(x + 13)


What is the factorization of -x2 - 11x plus 26?

-1(x-13)(x+2). APEX Answer


What is the factorization of -x2-11x plus 26?

(x + 13)(2 - x)


What is the factorization of -x-11x 26?

If you meant to write -x2 - 11x + 26, that factors to -(x - 2)(x + 13)


What is 11x plus 2 equals 26 plus 7x?

11x + 2 = 26 + 7x Subtract 7x from both sides: 4x + 2 = 26 Subtract 2 from both sides: 4x = 24 Divide both sides by 4: x = 6


What does x2 plus 11x plus 10 equals x2 plus 13x equal?

572 Because 2x11=22 and 13x2=26 and 22x26=572.


-x2 - 11x plus 26?

Although the question does not state, I will assume the purpose is to factor -x2 - 11x + 26 Find factors of 26: 1 and 26; 2 and 13. The goal is to use these factors to arrive at the number in the middle, 11. Which means the 1 and 26 will not work. Because the first coefficient is negative, when you separate your equation, one x must be positive, one must be negative, as below. ANS: (-x - 13)(x - 2)


What is the prime factorization of the number 26?

The prime factorization of the number 26 is: 2 x 13