Do you mean x2+11x-26 if so then it is (x-2)(x+13) when factored
Divide all terms by -1 so: x2-11x-26 = (x+2)(x-13) when factored
-x2 + 11x + 26 = -(x - 13)(x + 2) = (13 - x)(x + 2) = (x - 13)(-x - 2)
-1(x-13)(x+2). APEX Answer
572 Because 2x11=22 and 13x2=26 and 22x26=572.
-(x + 13)(x - 2)
Do you mean x2+11x-26 if so then it is (x-2)(x+13) when factored
Divide all terms by -1 so: x2-11x-26 = (x+2)(x-13) when factored
-x2 + 11x + 26 = -(x - 13)(x + 2) = (13 - x)(x + 2) = (x - 13)(-x - 2)
-x2 - 11x + 26= -x2 - 13x + 2x + 26= (2x - x2) + (26 - 13x)= x(2 - x) + 13(2 - x)= (2 - x)(x + 13)
-1(x-13)(x+2). APEX Answer
(x + 13)(2 - x)
If you meant to write -x2 - 11x + 26, that factors to -(x - 2)(x + 13)
11x + 2 = 26 + 7x Subtract 7x from both sides: 4x + 2 = 26 Subtract 2 from both sides: 4x = 24 Divide both sides by 4: x = 6
572 Because 2x11=22 and 13x2=26 and 22x26=572.
Although the question does not state, I will assume the purpose is to factor -x2 - 11x + 26 Find factors of 26: 1 and 26; 2 and 13. The goal is to use these factors to arrive at the number in the middle, 11. Which means the 1 and 26 will not work. Because the first coefficient is negative, when you separate your equation, one x must be positive, one must be negative, as below. ANS: (-x - 13)(x - 2)
The prime factorization of the number 26 is: 2 x 13