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Although the question does not state, I will assume the purpose is to factor -x2 - 11x + 26
Find factors of 26: 1 and 26; 2 and 13. The goal is to use these factors to arrive at the number in the middle, 11. Which means the 1 and 26 will not work.
Because the first coefficient is negative, when you separate your equation, one x must be positive, one must be negative, as below.
ANS: (-x - 13)(x - 2)
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What is the factorization of this trinomial -x2 - 11x plus 26?
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)
What does x2 plus 11x plus 10 equals x2 plus 13x equal?
572 Because 2x11=22 and 13x2=26 and 22x26=572.
What is the factorization of -x2 - 11x plus 26?
-1(x-13)(x+2). APEX Answer
What is the factorization of the trinomial x2 11x - 26?
Do you mean x2+11x-26 if so then it is (x-2)(x+13) when factored
What is the factorization of the trinomial -x2 11x 26?
Divide all terms by -1 so: x2-11x-26 = (x+2)(x-13) when factored
