Assuming the missing symbols are pluses, that factors to (x + 4)(x + 1)
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x2-5x+4 = (x-1)(x-4) when factored
If you mean: x2+5x+4 = 0 then the solutions are x = -1 and x = -4
To solve for x: x2 = 5x + 2 x2 - 5x = 2 x2 - 5x + (5/2)2 = 2 + (5/2)2 (x - 5/2)2 = 8/4 + 25/4 x - 5/2 = ± √(33/4) x = (5 ± √33) / 2
-x2 + 5x - 4 = 0. Then, x2 - 5x + 4 = (x - 4)(x - 1) = 0; whence, x = 1 or 4. Checking, -1 + 5 - 4 = 0; and -16 + 20 - 4 = 0.
(x + 4)(x + 1)