The correct factorization of 5 x plus 2 -3x x plus 2 is 2x+4.
3x2 - 3x - 60 = 3(x2 - x - 20) = 3(x2 - 5x + 4x - 20) = 3(x[x - 5] + 4[x - 5]) = 3(x + 4)(x - 5)
(5x + 6)(x + 4)
x2-7x-44 (x-11)(x+4)
(x + 4)(x + 8)
Assuming that x2 is x squared: (x - 9)(x + 4)
x2-5x+4 = (x-1)(x-4) when factored
(x+1)(x+4)
It is (x - 9)*(x + 4)
x2-5x+4 = (x-1)(x-4) when factord
The factorization of 25x2 + 40x + 16 is (5x+4)(5x+4).
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
-x2 + 5x - 4 = 0. Then, x2 - 5x + 4 = (x - 4)(x - 1) = 0; whence, x = 1 or 4. Checking, -1 + 5 - 4 = 0; and -16 + 20 - 4 = 0.
Assuming the missing symbols are pluses, that factors to (x + 4)(x + 1)
The factors of x2 + 5x + 4 would be (x + 1) and (x + 4)
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
5x2 + 9x + 4 = (x + 1)(5x + 4).