0
Here's a good old reliable formula that typically shows up with time in seconds,
but if we're careful and keep everything consistent, there's no reason that it
shouldn't work just as well for this situation, with the time in hours:
Distance = s0 T + 1/2 A T2
Distance = 100 km
s0 = initial speed = 150 km/hr
A = acceleration = 200 km/hr2
Let's see what that does for us:
100 = 150 T + 100 T2
T2 + 1.5 T - 1 = 0
T = 1/2 [ -1.5 ± sqrt(2.25 + 4) ] = 1/2 [ -1.5 ± sqrt(6.25) ]
T = 1/2 hr
T = -2 hr
The solution T=-2 hr is technically perfect, mathematically impeccable,
and realistically useless. We'll use the solution T=0.5 hour .
-- T = 0.5 hour when the train has covered 100 km.
-- In 1/2 hour, its speed has increased by 1/2 of the acceleration value = 100 km/hr.
-- With its muzzle velocity of 150 km/hr, the bullet train's speed after the 1/2 hour is 250 km/hr .
What else can I help you with?
If you know the distance traveled and the time traveled can YOU determine an object and ACCELERATION?
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
What is Galileo's formula with distance accleraction and time?
distance equals initial velocity times change in time interval plus half of accerlation plus time interval squared
What is 20.72 km squared rounded to the nearest square kilometer?
21 km squared
How do you calculate tota distance traveled when given velocity time and acceleration?
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
How do you calculate velocity final with distance and acceleration?
aSsuming constant acceleration, and movement along a line, use the formula: vf2 = vi2 + (1/2)at2 (final speed squared equals initial speed squared plus one-half times acceleration times time squared).
What does initial velocity squared plus 2 times acceleration times distance equal?
This equation represents the final velocity squared when an object is accelerating from an initial velocity over a certain distance. It is derived from the kinematic equation (v^2 = u^2 + 2as), where (v) is the final velocity, (u) is the initial velocity, (a) is the acceleration, and (s) is the distance traveled.
What is the formula for calculating distance when an object is accelerating at a constant rate, given by the equation distance 1/2at2?
The formula for calculating distance when an object is accelerating at a constant rate is distance 1/2 acceleration time squared.
How do you calculate the initial speed?
v2 = u2+ 2as where v squares is the final velocity , u squared is the initial velocity , a is the acceleration and s is the distance travelled. If it is free fall take a = 10m/s squared ( as gravity ).
How many meters squared are in a kilometer squared?
1 sq kilometer = 1000000 sq meters
How many meters are in a kilometer squared?
One kilometer squared equates to one million meters squared.
How many squared meters is in 1 squared kilometer?
a million.
If you know the distance traveled and the time traveled can YOU determine an object and ACCELERATION?
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
How many centimeters squared are in one kilometer squared?
1 Square kilometer is 10 000 000 000 square centimeters
How many areas are in a kilometer squared?
1 square kilometer 1x1=1
What is Galileo's formula with distance accleraction and time?
distance equals initial velocity times change in time interval plus half of accerlation plus time interval squared
What is 20.72 km squared rounded to the nearest square kilometer?
21 km squared
The box decelerates at a rate of 3 m s and skids 24 meters before coming to a stop How fast were you traveling when the box fell out?
To find the initial velocity of the box when it fell out, you can use the formula: final velocity squared = initial velocity squared + 2 * acceleration * distance. Given that the final velocity is 0 m/s, acceleration is 3 m/s^2, and distance is 24 meters, you can solve for the initial velocity.
