Need set of point parabola passes through.
X = 1
Y = 8
----------------(1, 8)
For focus,
X2 = 4pY
insert values, solve for p
(1)2 = 4p(8)
= 1/32
=======focus
- 1/32
=======directrix
( long time since I have done this. Formula is correct, check my math )
x=3
5x2=8x Divide with x on both sides5x= 8 Solve xx=8/5
If: x^2 -8x = -12 then x^2-8x+12 = 0 and so x = 2 or x = 6
(x - 6)(x - 2)
(x-3)(x-5) = 0
x=3
5x2=8x Divide with x on both sides5x= 8 Solve xx=8/5
If: x^2 -8x = -12 then x^2-8x+12 = 0 and so x = 2 or x = 6
(x - 6)(x - 2)
(x + 4)(x +4) or (x + 4)squared
(x-3)(x-5) = 0
x^(2) + 8x + 8y +32 = 0 Then -8y = x^(2) + 8x + 32 y = (-x^(2)/8) - x - 4 In standard parabolic form. The coefficient of x^(2) is '-1/8' . It will be an 'umbrella' shaped parabola.
8x squared
2
23
the answer of √8x+16-3x=0 is x= 0.447213595 = +/- 0.447(to 3 decimal places) if I'm not mistaken
12x2 + 8x = 0 4x(3x + 2) = 0 Two solutions: 1. x = 0 2. x = -2/3