yes!
The equation y = 4x^2 + 5 is a parabola
It is a parabola with its vertex at the origin and the arms going upwards.
The equation does not represent that of a parabola.
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
yes!
The equation y = 4x^2 + 5 is a parabola
It is a parabola with its vertex at the origin and the arms going upwards.
Their noses are both at the origin, and they both open upward, but y=4x2 is a much skinnier parabola.
y=4x2+3x+8
I think you are talking about the x-intercepts. You can find the zeros of the equation of the parabola y=ax2 +bx+c by setting y equal to 0 and finding the corresponding x values. These will be the "roots" of the parabola.
The equation does not represent that of a parabola.
You would convert it to vertex form by completing the square. You can also find the optimum value as optimum value and vertex are the same.
First you need to solve for y. So write 4x2+y=16 so y=16-4x2 Now write f(x)=16-4x2
No. [ y = 4x2 ] is a quadratic equation.
It is an up parabola.
Y = X2 forms a parabola