Their noses are both at the origin, and they both open upward,
but y=4x2 is a much skinnier parabola.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Assuming the first function is y = 4x2 + 1, and the second y = 4x2 then the first graph is 1 unit higher than the second.
No translation will invert a quadratic graph.
Therefore x2=9+y2. And x is the square-root of that (with two values plus and minus). Choose a value of y, and work out x2 and therefore the values of x. Plot the two (+ and -) on a graph and continue for more values of y.
x2+y2=1 : parent function in y form: y=-+(square root)(x2+1) to graph you need two diffrent equations one in positive form the other in negitive.
Just one. It's at the origin. (0, 0)
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Assuming the first function is y = 4x2 + 1, and the second y = 4x2 then the first graph is 1 unit higher than the second.
No translation will invert a quadratic graph.
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
the graph is moved down 6 units
No.
y=x2+4x+1
9
y=x2
1
y = - x2 +6x - 5.5
x2+(y-x2/3)2=1
y = x2 + 4 The graph is a parabola, with its nose at y=4 on the y-axis, and opening upward.