It depends on the size of your rotor
g=(1.118x10^-5)xradius of rotor in cm x speed of centrifuge in rev/min^2
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To convert 3000 revolutions per minute (rpm) into gravitational force (g), you can use the formula for centripetal acceleration: ( a = \frac{(2\pi \times \text{rpm})^2 \times r}{60^2} ). Here, ( r ) is the radius in meters. To express acceleration in terms of g, divide the result by the acceleration due to gravity (approximately 9.81 m/s²). The final result will give you the acceleration in g's.
It depends upon the circumference of the rotating object such as a wheel. Deriving the formula, let the radius of the wheel be r then, the circumference of a circle is = (2 X (pi) X r) the total distance covered by the wheel in one min = (2 X (pi) X r) X rpm now, if the object's diameter is measured in meters then the formula would be, (2 X (pi) X r X rpm X 60) / 1000 else if in different unit then just convert it to meters
km=1000m
Seconds/3600 = Hours
800 gType your answer here...