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It is my first answer.

Is the problem to solve A=B^X ?

where A and B are positive integers

and X the power exponent of B The given equation can be rewritten in a logarithm form.

Log A = X * Log B

solving for a unique X

X = Log A / Log B The result: Any positive integer A can be rewritten as a positive integer B to the distinct power X. Where X is Log A divided by Log B A = B ^(Log A / Log B) I think, this is the solution.

Roger Verbeeck

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17y ago

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