There is no formula that will generate all the prime numbers less than or equal to 500.
Perhaps the "next best thing" is that there are some formulas that will generate prime numbers for certain values that are plugged in to the formula, but not necessarily all the prime numbers.
For example, the formula n2 - n + 41 will generate prime numbers for all values of n from 0 to 40, but not for all values greater than or equal to 41. But even for values of n that are less than or equal to 40, while the formula will result in a Prime number, it doesn't generate all the prime numbers. The first few prime numbers generated by this formula (for n = 0, 1, 2, 3, 4, and 5) are 41, 41, 43, 47, 53, and 61. But many prime numbers get "skipped over" by using this, or any other, formula.
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The cube root of 5000 is approx 17.1 So the numbers 1 to 17 have cubes which are smaller than 5000 that is, there are 17 such numbers.
Here's a start umbers=[True]*5001 index=2 primes=[] while index<5000: multiplier=2 while index*multiplier <= 5000: Numbers[index*multiplier]=False multiplier+=1 index+=1 while Numbers[index]==False and index < 5000: index+=1 for x in range(0,5000): if Numbers[x]==True: primes.append(x) x+=1 print primes
The first three whole numbers after 5000 are 5001, 5002, and 5003. Whole numbers are non-negative integers, so they include all positive integers starting from zero. In this case, we are simply counting sequentially from 5000 onwards to arrive at the next three whole numbers.
On converting between Arabic and Roman Numbers ,we get : 5000 IN ROMAN NUMERALS is written as : _ V
5000 is an even numberEven numbers end with 0, 2, 4, 6, and 8.Odd numbers end with 1, 3, 5, 7, and 9.