Chat with our AI personalities
x-1 and x+1 are consecutive to x, the first before it and the second after it.
The first three even numbers are 2, 4, and 6. To find the product of these numbers, you simply multiply them together: 2 x 4 x 6 = 48. Therefore, the product of the first three even numbers is 48.
The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.The formula for the sum of an arithmetic sequence is ((first number) + (last number)) x (how many numbers) / 2, in this case, (1 + 100) x 100 / 2.
First 125 numbers sum to 125/2 x 126, so first 125 even numbers sum to double that ie 125 x 126 = 15750
Since they are consecutive even numbers, once you pick x to be the first number, the next even number is x + 2, and then x + 4. x + (x+2) + (x+ 4) = 180 3x + 6 = 180 3x = 174 x = 58 x+2 = 60 x+4 = 62