A rounded rectangle is not a function at all.
Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.
Area of rectangle: (x+5)(3x-7) = 3x2+8x-35
crossed rectangle is not a rectangle, rectangle have to have 90 degree angles.
In a flowchart, a function call is typically represented by a rectangle or a rounded rectangle that contains the name of the function being called. This shape indicates a process or operation, and it may include input parameters and expected outputs. Arrows lead to and from this shape to show the flow of control and the sequence of operations. Additionally, any return values can be depicted with a separate arrow leading back to the calling process.
A rounded rectangle is not a function at all.
The size of the circle is a function of the height of the rectangle.
The average value of a function is the equivalent area of the function expressed like a rectangle .- Thus If you have an area A from limits a and b , the equivalent is : (b-a) H ( rectangle area ) = INT f(x) dx , then average H is H= ( INT f(x) dx) /(b-a)
Let the length of the rectangle be represented by ( l ). Then, the width can be expressed as ( w = l - 6 ). The area ( A ) of the rectangle is given by the product of its length and width, so ( A = l \times w = l \times (l - 6) ). This simplifies to the quadratic function ( A(l) = l^2 - 6l ).
There will be a function in it like this: double RectangleArea (double a, double b) { return a*b; }
Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.
Area of rectangle: (x+5)(3x-7) = 3x2+8x-35
The area of a rectangle with a width of x units and a length of (x + 3) units
Suppose the length and width of the rectangle are L and W metres respectively.Then the perimeter, P = 20 m implies that2(L + W ) = 20 => L + W = 10 or W = 10 - L.Then Area = L * W = L * (10 - L) sq metres.
If the perimiter is 20 and one side is [[length]] then the other side is (10 - [[length]]). So the area is: [[length]] x (10 - [[length]]) square metres.
crossed rectangle is not a rectangle, rectangle have to have 90 degree angles.
To draw a rectangle in Turbo Pascal, you can use the Rectangle procedure from the Graph unit. First, initialize the graphics mode with InitGraph, then specify the coordinates for the top-left and bottom-right corners of the rectangle. Use the Rectangle function with these coordinates, and finally, use CloseGraph to exit the graphics mode. Here’s a simple example: uses Graph; var gd, gm: Integer; begin gd := Detect; InitGraph(gd, gm, ''); Rectangle(100, 100, 300, 200); // Draws a rectangle ReadLn; // Wait for user input CloseGraph; end.