A rounded rectangle is not a function at all.
Area of rectangle: (x+5)(3x-7) = 3x2+8x-35
Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.
crossed rectangle is not a rectangle, rectangle have to have 90 degree angles.
In a flowchart, a function call is typically represented by a rectangle or a rounded rectangle that contains the name of the function being called. This shape indicates a process or operation, and it may include input parameters and expected outputs. Arrows lead to and from this shape to show the flow of control and the sequence of operations. Additionally, any return values can be depicted with a separate arrow leading back to the calling process.
A rounded rectangle is not a function at all.
The size of the circle is a function of the height of the rectangle.
The average value of a function is the equivalent area of the function expressed like a rectangle .- Thus If you have an area A from limits a and b , the equivalent is : (b-a) H ( rectangle area ) = INT f(x) dx , then average H is H= ( INT f(x) dx) /(b-a)
There will be a function in it like this: double RectangleArea (double a, double b) { return a*b; }
Area of rectangle: (x+5)(3x-7) = 3x2+8x-35
Area of a rectangle is length x width. It isn't clear what the width is in this case - or how you could solve for it.
The area of a rectangle with a width of x units and a length of (x + 3) units
Suppose the length and width of the rectangle are L and W metres respectively.Then the perimeter, P = 20 m implies that2(L + W ) = 20 => L + W = 10 or W = 10 - L.Then Area = L * W = L * (10 - L) sq metres.
crossed rectangle is not a rectangle, rectangle have to have 90 degree angles.
If the perimiter is 20 and one side is [[length]] then the other side is (10 - [[length]]). So the area is: [[length]] x (10 - [[length]]) square metres.
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.
Rectangle area = (rectangle width) x (rectangle height)