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What is the area of a rectangle is the length is 16 and the primeter is 56?
The area of rectangle is : 896.0
How do you find the area of rectangle using function?
The area is the length times the width. That's the function. If you want to write a function in a computer language, you need two parameters. Just return the product of the two parameters. Example in Java: double rectangle_area(double length, double width) { return length * width; } I didn't test this, but that's the basic idea.
How do you look at a graph and tell what the quadratic function i?
To determine the quadratic function from a graph, first identify the shape of the parabola, which can open upwards or downwards. Look for key features such as the vertex, x-intercepts (roots), and y-intercept. The standard form of a quadratic function is ( f(x) = ax^2 + bx + c ), where ( a ) indicates the direction of the opening. By using the vertex and intercepts, you can derive the coefficients to write the specific equation of the quadratic function.
The length of a rectangle is 3 inches greater than the width Write a polynomial that represents the area of the rectangle?
let x be the width let x+3 be the length The area of a rectangle is length X width Area=(x)(x+3) =x^2+3x
Write a C programme for area of rectangle?
Here's a simple C program to calculate the area of a rectangle: #include <stdio.h> int main() { float length, width, area; printf("Enter length of the rectangle: "); scanf("%f", &length); printf("Enter width of the rectangle: "); scanf("%f", &width); area = length * width; printf("Area of the rectangle: %.2f\n", area); return 0; } This program prompts the user to input the length and width, calculates the area, and then displays the result.
A rectangle's width is 6 feet less than its length Write a quadratic function that expresses the rectangle's area in terms of its length?
Let the length of the rectangle be represented by ( l ). Then, the width can be expressed as ( w = l - 6 ). The area ( A ) of the rectangle is given by the product of its length and width, so ( A = l \times w = l \times (l - 6) ). This simplifies to the quadratic function ( A(l) = l^2 - 6l ).
A rectangles width is 5 feet less than its length Write a quadratic function that expresses the rectangles area in terms of its length?
A(l)=l2-5l
Write a statement that does not represent a linear function?
The area of a rectangle with a width of x units and a length of (x + 3) units
What is the area of a rectangle is the length is 16 and the primeter is 56?
The area of rectangle is : 896.0
How do you find the area of rectangle using function?
The area is the length times the width. That's the function. If you want to write a function in a computer language, you need two parameters. Just return the product of the two parameters. Example in Java: double rectangle_area(double length, double width) { return length * width; } I didn't test this, but that's the basic idea.
How do you look at a graph and tell what the quadratic function i?
To determine the quadratic function from a graph, first identify the shape of the parabola, which can open upwards or downwards. Look for key features such as the vertex, x-intercepts (roots), and y-intercept. The standard form of a quadratic function is ( f(x) = ax^2 + bx + c ), where ( a ) indicates the direction of the opening. By using the vertex and intercepts, you can derive the coefficients to write the specific equation of the quadratic function.
The length of a rectangle is 3 inches greater than the width Write a polynomial that represents the area of the rectangle?
let x be the width let x+3 be the length The area of a rectangle is length X width Area=(x)(x+3) =x^2+3x
Write an algorithm to find the root of quadratic equation?
Write an algorithm to find the root of quadratic equation
Write a C programme for area of rectangle?
Here's a simple C program to calculate the area of a rectangle: #include <stdio.h> int main() { float length, width, area; printf("Enter length of the rectangle: "); scanf("%f", &length); printf("Enter width of the rectangle: "); scanf("%f", &width); area = length * width; printf("Area of the rectangle: %.2f\n", area); return 0; } This program prompts the user to input the length and width, calculates the area, and then displays the result.
How do you take a quadratic function and write it in standard form?
The question i have to convert to standard form is -1/2(x-6)2
The width of a rectangle is 61 cm and its length is 71 cm Write the ratio of its width to its length as a fraction?
61:71 1:71/61
Write a program to accept length and breadth of a rectangle and then calculate its area and print it?
int length int breadth int area= (length x breadth) print area
