prove that every metric space is hausdorff and first countable
I posted this question myself to be honest because i wasn't sure... but the horizontal line test was made to prove whether the function/graph was an one-to-one function
How would you prove algebraically that the function: f(x)= |x-2|, x<= 2 , is one to one?
There is no mathematical proof that space is infinite. All we know is that there is an expanding limit to what we can see.
Assuming the function is linear, the direction of the function can be determined by the coefficient's sign:[y = mx + b]Where m is the coefficient of x, if m is negative, then the function is increasing. If m is positive, the function is decreasing (this relationship is rather complicated and requires advanced calculus to prove).
prove that every metric space is hausdorff and first countable
Inflate a balloon.
The answer depends on what you wish to prove!
How would you prove algebraically that the following function is one to one? f(x)= (x+3)^2 , x>= -3?
I posted this question myself to be honest because i wasn't sure... but the horizontal line test was made to prove whether the function/graph was an one-to-one function
To require users to prove who they are
Looking at the graph of the function can give you a good idea. However, to actually prove that it is even or odd may be more complicated. Using the definition of "even" and "odd", for an even function, you have to prove that f(x) = f(-x) for all values of "x"; and for an odd function, you have to prove that f(x) = -f(-x) for all values of "x".
How would you prove algebraically that the function: f(x)= |x-2|, x<= 2 , is one to one?
Curiosity and ego, to prove it could be done.
You can look at a picture of it taken from space, or the moon
There is no mathematical proof that space is infinite. All we know is that there is an expanding limit to what we can see.
Calling an in-line function, which is not actually a function-call.