The genotypic ratio of a cross of Aa and Aa is: one AA, one aa, and two Aa. Or 1:2:1
F1 offspring obtained by monohybrid cross of AA and AA will be Aa.
offspring will be produced in following AA :Aa:aa and is in the ratio of 1:2:1 so the probabiltiy is 50%
There is nothing true about the AAA theorem and the SSS postulate because the AAA postulate is not true!
there isn't a AAA postulate because,,, for a triangle to be equal, there HAS to be a side in it
A
The genotypic ratio for two parents with the genotypes AAA and AAA is 1:0. This means that all offspring will have the genotype AAA.
The predicted ratio of offspring in a mating of AAA and AAA would be 100% AAA. Since both parents have the same genotype, all of their offspring will inherit the same genotype.
25%
F1 offspring obtained by monohybrid cross of AA and AA will be Aa.
A Punnett square for AAA x AAA offspring that is AAA would result in a ratio of 1:0, meaning all offspring would have the genotype AAA. Therefore, the number of boxes required would be 1.
offspring will be produced in following AA :Aa:aa and is in the ratio of 1:2:1 so the probabiltiy is 50%
The offspring's genotype will be AA. Both parents are homozygous dominant, AA, having only dominant alleles to pass on to their offspring. So each parent can pass on only the dominant allele (A) to its offspring. So the offspring will also be homozygous dominant, AA.
For the two given parents: 1 offspring will have the homozygous genotype: YY 1 offspring will have the homozygous genotype: yy 2 offspring will have the heterozygous genotype: Yy
No, an AAA and SS combination can only produce an Aa genotype. The offspring will inherit one allele from each parent, resulting in a heterozygous genotype. For an AAA genotype to be produced, both parents must have the same alleles for the specific gene.
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AAa
B a g b a g ggg aaa b a g