F1 offspring obtained by monohybrid cross of AA and AA will be Aa.
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Asuming that the F1 generation is heterozygous for a single trait and that the F2 cross is of 2 F1 offspring. Ex. Aa X Aa the phenotypic ratio is 3:1 dominant to recessive. The genotypic ratio is 1:2:1 AA:Aa:aa.
Straight thumbs, hitch hiker's thumb is recessive...so the F1 generation in this example would be heterozygous and have the dominant (straight thumbed) phenotype.
If the value changes from fraction1 (F1) to fraction 2 (F2), then the percentage change is 100*(F2/F1 - 1) provided F1 > 0. If F1 is 0 then the value is not defined, and if F1 <0 you get nonsense results.
No
f1 is a 83 model (no front disc brake)not 84 f1 f2 were aus europe e1 e2 were USA only differance I saw on my f2 to the e2 was the front disc was different then in 85 there were all e3 and the the rear swing arm was a straight box design