The answer is 998.
Th e greatest 4-digit even number is 9,998 .
998
There are 898 three-digit even numbers. Nine of them are multiples of 55. That leaves 889 * * * * * There are 450 three-digit even numbers and 17 of them are multiples of 55. So that leaves 433.
odd
To form three-digit even numbers from the set {2, 3, 5, 6, 7}, we can use the digits 2 or 6 as the last digit (to ensure the number is even). For each case, we can choose the first two digits from the remaining four digits. For three-digit numbers, there are 2 options for the last digit and (4 \times 3 = 12) combinations for the first two digits, resulting in (2 \times 12 = 24) even numbers. For four-digit even numbers, we again have 2 options for the last digit. The first three digits can be selected from the remaining four digits, giving us (4 \times 3 \times 2 = 24) combinations for each last digit. Thus, there are (2 \times 24 = 48) even four-digit numbers. In total, there are (24 + 48 = 72) three-digit and four-digit even numbers that can be formed from the set.
Th e greatest 4-digit even number is 9,998 .
9998
998
198 is the greatest three-digit even number that has no factor equal to 4.
No. Three-digit numbers start with 100.
998.
998
There are 898 three-digit even numbers. Nine of them are multiples of 55. That leaves 889 * * * * * There are 450 three-digit even numbers and 17 of them are multiples of 55. So that leaves 433.
999 is the greatest 3 digit number and it is odd because it ends with a 9.
odd
There are 450 even three-digit integers, from 100 to 998. This excludes numbers with leading zeroes (000 to 099).
well, it's not 999 because that's odd ... can't see why it wouldn't be 998, which is the greatest even three-digit number, and since all even numbers besides 2 are composite, it must also be the greatest three-digit composite even number