Heat loss due to change in temperature:
Q = mc(T2-T1)
Heat loss due to change in phase:
Q = mL
c and L are constants that are specific to each compound at certain temperatures. For water, we usually take c to be 4186 J/(kg*K).
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If you're looking for an equation that describes the loss of heat of an object in terms of time and the ambient temperature I would recommend Newton's law of cooling. Look for it here http://www.ugrad.math.ubc.ca/coursedoc/math100/notes/diffeqs/cool.html
Heat loss of water: The surface area effects the the rate of heat loss because the rate of heat loss increases if the surface are is higher. How: The water is spread out into a bigger space meaning the
Yes, it is.
Lift/Drag x Height loss
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