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according to the pythagoras theorem, In a right angled triangle,

(hypotenuse)2 = (side)2 + (side)2

here, 2 sides are given, that are 5cm and 6cm (or it can be in meter )

so by pythagoras theorem we get,

(hypotenuse)2 = (side)2 + (side)2(hypotenuse)2 = 52 + 62(hypotenuse)2 = 25 + 36(hypotenuse)2 = 61hypotenuse = √61
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Q: What is the hypotenuse with the lengths of 5 and 6?
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