according to the pythagoras theorem, In a right angled triangle,
(hypotenuse)2 = (side)2 + (side)2
here, 2 sides are given, that are 5cm and 6cm (or it can be in meter )so by pythagoras theorem we get,
(hypotenuse)2 = (side)2 + (side)2(hypotenuse)2 = 52 + 62(hypotenuse)2 = 25 + 36(hypotenuse)2 = 61hypotenuse = √61The length of the hypotenuse of a right triangle with legs of lengths 6 and 8 inches is: 10 inches.
Its hypotenuse is 5 units in length
It is sqrt(6^2 + 5^2) = sqrt(36+25) = sqrt(61) = 7.8102, approx.
45
7.211
The length of the hypotenuse of a right triangle with legs of lengths 6 and 8 is: 10
The length of the hypotenuse of a right triangle with legs of lengths 6 and 8 inches is: 10 inches.
The length of the hypotenuse of a right triangle with legs of lengths 5 and 12 units is: 13The length of a hypotenuse of a right triangle with legs with lengths of 5 and 12 is: 13
Its hypotenuse is 5 units in length
It is sqrt(6^2 + 5^2) = sqrt(36+25) = sqrt(61) = 7.8102, approx.
45
7.211
The length of the hypotenuse works out as the square root of 41
41
5 sqrt(2) = 7.071 (rounded)
6.4031 (rounded)
10 units in length