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What is the length of the hypotenuse of a right triangle with legs of lengths 5 and 7?
To answer this question, use the pythagorean theorem: a^2+b^2=c^2, where a and b are leg lengths and c is the length of the hypotenuse. Then isolate c, the length of the hypotenuse. c=sqrt(a^2+b^2) At this point, simply plug in the leg lengths, 5 and 7, in for a and b. c=sqrt(5^2+7^2) c=sqrt(25+49) c=sqrt(74)
How many 1.4 metre lengths can be cut out from a 7 metre piece?
Five lengths because 7/1.4 = 5
Could 4 7 7 be side lengths of a triangle?
Yes and the given lengths would form an isosceles triangle.
The lengths of 2 sides of an isosceles triangle are 7 and 5 what are all the possible lengths of the third side?
An isosceles triangle must have two sides of equal size.Since you have a side of 7 and 5, for it to be isosceles, your third side must be either 7 or 5.
What are the lengths of the tangent lines from the point 7 -2 to the circle x2 plus y2 -10y -24 equals 0 on the Cartesian plane?
Equation of circle: x^2 +y^2 -10y -24 = 0 Completing the square: x^2+(y-5)^2 = 49 Center of circle: (0, 5) Radius of circle: 7 Distance from (7, -2) to (0, 5) = sq rt of 98 and is the hypotenuse of a right triangle Using Pythagoras: theorem: distance^2 minus radius^2 = 49 Therefore lengths of tangent lines are square root of 49 = 7 units
