7
-19
7
With n dice* the most common outcome can be found from: most_common = 7n ÷ 2 If n is odd, this results in a fraction and there are actually two most common results which are the whole numbers either side of the fraction (eg with 3 dice, the most common value given above is 21/2 = 10½ which means that the most common value with 3 dice is 10 or 11 - both occur with the same frequency). For two dice this gives: most_common = (7 × 2) ÷ 2 = 7. * As the word "dice" is the plural of the word "die", n > 1.
There are 21 possible combinations of 2 dice. The total with the most possible combinations is 7, which has three. (6+1,5+2,4+3) This is not right. By this logic 6 and 8 have equal chances of being rolled as I can roll a six through the numbers, 5-1, 4-2, 3-3. When counting the probability of a number to be rolled you have to assume the dice do not care the order in which they are rolled. That is to say, a roll of 5-2, and 2-5 are NOT the same. It is for this reason we find that 7 truly has many more ways a being rolled. 2-5, 5-2, 6-1, 1-6, 3-4, 4-3. While both 6 and 8 have less because one of their dice rolls cannot be counted twice the double roll. For six this is the 3-3 roll, and for eight its the 4-4 roll. That is why 7 is the most common roll on two dice.
5
7
The most common number would be 10 and 11. When using 3 dice, the total sum of eyes must be between 3 and 18. The most probably number being rolled can be found simply by calculating the average of the highest and lowest possibilities. (3+18)/2 = 10,5 ; meaning 10 and 11 are the two most probable numbers to be rolled using 3 dice.
-19
7
if it's a casino die then it is a fair die where all sides have the same probability of being rolled. if it's an indented die then six is the most common # because the one side has more weight
With n dice* the most common outcome can be found from: most_common = 7n ÷ 2 If n is odd, this results in a fraction and there are actually two most common results which are the whole numbers either side of the fraction (eg with 3 dice, the most common value given above is 21/2 = 10½ which means that the most common value with 3 dice is 10 or 11 - both occur with the same frequency). For two dice this gives: most_common = (7 × 2) ÷ 2 = 7. * As the word "dice" is the plural of the word "die", n > 1.
There are 21 possible combinations of 2 dice. The total with the most possible combinations is 7, which has three. (6+1,5+2,4+3) This is not right. By this logic 6 and 8 have equal chances of being rolled as I can roll a six through the numbers, 5-1, 4-2, 3-3. When counting the probability of a number to be rolled you have to assume the dice do not care the order in which they are rolled. That is to say, a roll of 5-2, and 2-5 are NOT the same. It is for this reason we find that 7 truly has many more ways a being rolled. 2-5, 5-2, 6-1, 1-6, 3-4, 4-3. While both 6 and 8 have less because one of their dice rolls cannot be counted twice the double roll. For six this is the 3-3 roll, and for eight its the 4-4 roll. That is why 7 is the most common roll on two dice.
If any numbers come up more often than any others over the long run, then the dice are loaded and the game is not honest. * * * * * That is true for the roll of a die, but not dice. With 2 dice, the probabilities of the numbers are as follows 2 or 12 : 1/36 each 3 or 11 : 2/36 or 1/18 each 4 or 10 : 3/36 or 1/12 each 5 or 9 : 4/36 or 1/9 each 6 or 8 : 5/36 each 7 : 6/36 or 1/6 So 7 is the most rolled number in the long run when 2 dice are rolled.
4
Seven.
It is generally accepted as referring to the fact that a three rolled in most dice games is a losing roll; "keeps coming up threes" is a run of bad luck