There are 21 possible combinations of 2 dice. The total with the most possible combinations is 7, which has three. (6+1,5+2,4+3)
This is not right. By this logic 6 and 8 have equal chances of being rolled as I can roll a six through the numbers, 5-1, 4-2, 3-3. When counting the probability of a number to be rolled you have to assume the dice do not care the order in which they are rolled. That is to say, a roll of 5-2, and 2-5 are NOT the same. It is for this reason we find that 7 truly has many more ways a being rolled. 2-5, 5-2, 6-1, 1-6, 3-4, 4-3. While both 6 and 8 have less because one of their dice rolls cannot be counted twice the double roll. For six this is the 3-3 roll, and for eight its the 4-4 roll. That is why 7 is the most common roll on two dice.
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For normal dice, and assuming "combined" refers to the sum, the answer is 7.
Ten-sided dice are often used in games that require a "percentage roll", such as Dungeons & Dragons. Players roll two 10-sided dice, and the numbers rolled are used as digits to form a number between 0 and 99. Using a "0" instead of "10" simplifies this process. For most other games and instances, zeroes on ten-sided dice represent tens. Just FYI - some ten-sided dice do actually have a "10" instead of a "0", but they're fairly rare. I got 4 of them in a board game called Filthy Rich, which - ironically enough - uses numerous references to rolling zeroes instead of tens. Go figure.
Assuming you are only rolling one die, then each of the six numbers (1,2,3,4,5,6) has an equal chance (1 sixth) of landing face up.
Answer 1:The odds are very easy to calculate. Simply divide the number of "valid" rolls against all possible rolls. For ease, you can write down all possible combination for the 2 dice.1-1; 1-2; 1-3; 1-4....and so on, remember 1-4 and 4-1 are different rollsThere are 36 unique possible combination, and 6 of them are doubles, so that's 6/36 chances (and since 6 goes into 36, 6 times, this reduces to 1/6) or about 17%Answer 2:Another way to look at this problem, generically, is to assume we have an 'n' face dice. In most cases, dice have 6 faces (1, 2, 3, 4, 5, 6). But why not create a solution that works for any number of sides? Well, if we are trying to calculate the probability of rolling two dice (dice-1 and dice-2) of 'n' sides at the same time and having them turn up as doubles, only one of the dice really matters. Here's why. Dice-1 is guaranteed to land on a number 1-n. This will happen every time (on a fair dice, disregarding freak incidents). What we are trying to calculate is the probability that dice-2 will land on the SAME number as dice-1. Dice-2 can only land on one of 'n' values: 1, 2, 3, 4, 5, 6, ... , 'n'. For you non math folks, this just means it must land on a number from 1 to 'n' where 'n' is the number of sides on your dice. Out of all of the sides that dice-2 can PHYSICALLY land on, one of the sides MUST necessarily have the same as the value that dice-1 landed on. That is to say, if dice-1 landed on the value 3, there must be some chance that dice-2 will also land on the value 3. The probability of this occurring on a fair die is 1 divided by the total number of possible outcomes, which would be 'n'. So, really, there is a 1/n chance that dice-2 will land on the same number as dice-1. Thus, our probability for rolling doubles is simple 1/n. For our 6 sided dice example, our dice-1 lands on some value between 1 and 6 and there is a 1/6 chance dice-2 will match it.
they are all equally likely, just like flipping a coin.
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The most common number would be 10 and 11. When using 3 dice, the total sum of eyes must be between 3 and 18. The most probably number being rolled can be found simply by calculating the average of the highest and lowest possibilities. (3+18)/2 = 10,5 ; meaning 10 and 11 are the two most probable numbers to be rolled using 3 dice.
2. This would be as a result of rolling a 1 on each of them.
Seven - there are more ways to make seven than there are to make any other number.
The most likely number is 7 since and here are the ways to get it: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1.
For normal dice, and assuming "combined" refers to the sum, the answer is 7.
Most likely it is a logarithm.
AnswerThe most likely number is seven.This can be 1+6, 2+5, 3+4, 4+3, 5+2, 6+1.Remember that dice have no memory - if you have rolled 7 three times in a row the odds of rolling another 7 does not change.this is all wrong don't listen that
#7
The most likely number to be rolled in craps is the number 7
Regular craps is played with 2 dice, but most casinos keep 5 dice on the table and the 3 the shooter isn't using are kept in a bowl.